If y = tanx + secx , prove that d^2y/dx^2 = cosx/(1-sinx)^2

 

If y = tanx + secx , prove that d^2y/dx^2 = cosx/(1-sinx) ^2

If have any doubt about this question or another question then you can comment below after few minutes you will get answers. 

Related Question

• Integrate ∫ [1/logx -1/(logx) ²] dx
• If y= x /√1-x^2 , Find d^3y / dx^3
• If y = √(1+x^2) ,Prove that d^4y /dx^4 = 12x^2 - 3/(1+ x^2) ^7/2
• Find the fourth order derivative of tanx
• If y = logx/x, show that d^2y/dx^2 =(2 logx - 3 ) / x^3
• If x = acosθ, y = bsinθ, find d^2y/dx^2
• If x=a(θ+sinθ), y=a(1+cosθ), find d^2y/dx^2 at θ=π/2